3(i-8)-8i=1+5(2i+1)

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Solution for 3(i-8)-8i=1+5(2i+1) equation: 



3(i-8)-8i=1+5(2i+1)

We move all terms to the left:

3(i-8)-8i-(1+5(2i+1))=0

We add all the numbers together, and all the variables

-8i+3(i-8)-(1+5(2i+1))=0

We multiply parentheses

-8i+3i-(1+5(2i+1))-24=0



We calculate terms in parentheses: -(1+5(2i+1)), so:

1+5(2i+1)

determiningTheFunctionDomain
5(2i+1)+1

We multiply parentheses

10i+5+1

We add all the numbers together, and all the variables

10i+6

Back to the equation:

-(10i+6)



We add all the numbers together, and all the variables

-5i-(10i+6)-24=0

We get rid of parentheses

-5i-10i-6-24=0

We add all the numbers together, and all the variables

-15i-30=0

We move all terms containing i to the left, all other terms to the right

-15i=30

i=30/-15

i=-2

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