3(j+1)+2=20

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Solution for 3(j+1)+2=20 equation:


Simplifying
3(j + 1) + 2 = 20

Reorder the terms:
3(1 + j) + 2 = 20
(1 * 3 + j * 3) + 2 = 20
(3 + 3j) + 2 = 20

Reorder the terms:
3 + 2 + 3j = 20

Combine like terms: 3 + 2 = 5
5 + 3j = 20

Solving
5 + 3j = 20

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 3j = 20 + -5

Combine like terms: 5 + -5 = 0
0 + 3j = 20 + -5
3j = 20 + -5

Combine like terms: 20 + -5 = 15
3j = 15

Divide each side by '3'.
j = 5

Simplifying
j = 5

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