3(j+1)=21

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Solution for 3(j+1)=21 equation:



3(j+1)=21
We move all terms to the left:
3(j+1)-(21)=0
We multiply parentheses
3j+3-21=0
We add all the numbers together, and all the variables
3j-18=0
We move all terms containing j to the left, all other terms to the right
3j=18
j=18/3
j=6

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