3(j+1)=3(-2j-1)-j

Solution for 3(j+1)=3(-2j-1)-j equation:

3(j+1)=3(-2j-1)-j

We move all terms to the left:

3(j+1)-(3(-2j-1)-j)=0

We multiply parentheses

3j-(3(-2j-1)-j)+3=0


We calculate terms in parentheses: -(3(-2j-1)-j), so:

3(-2j-1)-j

We add all the numbers together, and all the variables

-1j+3(-2j-1)

We multiply parentheses

-1j-6j-3

We add all the numbers together, and all the variables

-7j-3

Back to the equation:

-(-7j-3)


We get rid of parentheses

3j+7j+3+3=0

We add all the numbers together, and all the variables

10j+6=0

We move all terms containing j to the left, all other terms to the right

10j=-6

j=-6/10

j=-3/5