3(j+2)-j=2(j+1)

Solution for 3(j+2)-j=2(j+1) equation:

Simplifying
3(j + 2) + -1j = 2(j + 1)

Reorder the terms:
3(2 + j) + -1j = 2(j + 1)
(2 * 3 + j * 3) + -1j = 2(j + 1)
(6 + 3j) + -1j = 2(j + 1)

Combine like terms: 3j + -1j = 2j
6 + 2j = 2(j + 1)

Reorder the terms:
6 + 2j = 2(1 + j)
6 + 2j = (1 * 2 + j * 2)
6 + 2j = (2 + 2j)

Add '-2j' to each side of the equation.
6 + 2j + -2j = 2 + 2j + -2j

Combine like terms: 2j + -2j = 0
6 + 0 = 2 + 2j + -2j
6 = 2 + 2j + -2j

Combine like terms: 2j + -2j = 0
6 = 2 + 0
6 = 2

Solving
6 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.