3(j+20)-6=3

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Solution for 3(j+20)-6=3 equation: 



3(j+20)-6=3

We move all terms to the left:

3(j+20)-6-(3)=0

We add all the numbers together, and all the variables

3(j+20)-9=0

We multiply parentheses

3j+60-9=0

We add all the numbers together, and all the variables

3j+51=0

We move all terms containing j to the left, all other terms to the right

3j=-51

j=-51/3

j=-17

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