3(j+4)=21

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Solution for 3(j+4)=21 equation: 



3(j+4)=21

We move all terms to the left:

3(j+4)-(21)=0

We multiply parentheses

3j+12-21=0

We add all the numbers together, and all the variables

3j-9=0

We move all terms containing j to the left, all other terms to the right

3j=9

j=9/3

j=3

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