3(j+4)=4(j+1)

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Solution for 3(j+4)=4(j+1) equation: 



3(j+4)=4(j+1)

We move all terms to the left:

3(j+4)-(4(j+1))=0

We multiply parentheses

3j-(4(j+1))+12=0



We calculate terms in parentheses: -(4(j+1)), so:

4(j+1)

We multiply parentheses

4j+4

Back to the equation:

-(4j+4)



We get rid of parentheses

3j-4j-4+12=0

We add all the numbers together, and all the variables

-1j+8=0

We move all terms containing j to the left, all other terms to the right

-j=-8

j=-8/-1

j=+8

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