3(j+41)35=j

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Solution for 3(j+41)35=j equation: 



3(j+41)35=j

We move all terms to the left:

3(j+41)35-(j)=0

We add all the numbers together, and all the variables

-1j+3(j+41)35=0

We multiply parentheses

-1j+105j+4305=0

We add all the numbers together, and all the variables

104j+4305=0

We move all terms containing j to the left, all other terms to the right

104j=-4305

j=-4305/104

j=-41+41/104

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