3(j+5)=27

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Solution for 3(j+5)=27 equation: 



3(j+5)=27

We move all terms to the left:

3(j+5)-(27)=0

We multiply parentheses

3j+15-27=0

We add all the numbers together, and all the variables

3j-12=0

We move all terms containing j to the left, all other terms to the right

3j=12

j=12/3

j=4

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