3(j-5)+(8j+2)=7j-9

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Solution for 3(j-5)+(8j+2)=7j-9 equation: 



3(j-5)+(8j+2)=7j-9

We move all terms to the left:

3(j-5)+(8j+2)-(7j-9)=0

We multiply parentheses

3j+(8j+2)-(7j-9)-15=0

We get rid of parentheses

3j+8j-7j+2+9-15=0

We add all the numbers together, and all the variables

4j-4=0

We move all terms containing j to the left, all other terms to the right

4j=4

j=4/4

j=1

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