3(j-6)+12=-16+4j

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Solution for 3(j-6)+12=-16+4j equation: 



3(j-6)+12=-16+4j

We move all terms to the left:

3(j-6)+12-(-16+4j)=0

We add all the numbers together, and all the variables

3(j-6)-(4j-16)+12=0

We multiply parentheses

3j-(4j-16)-18+12=0

We get rid of parentheses

3j-4j+16-18+12=0

We add all the numbers together, and all the variables

-1j+10=0

We move all terms containing j to the left, all other terms to the right

-j=-10

j=-10/-1

j=+10

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