3(j-78)=12

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Solution for 3(j-78)=12 equation: 



3(j-78)=12

We move all terms to the left:

3(j-78)-(12)=0

We multiply parentheses

3j-234-12=0

We add all the numbers together, and all the variables

3j-246=0

We move all terms containing j to the left, all other terms to the right

3j=246

j=246/3

j=82

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