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3(k+1)+11k=2(4+5)+3
We move all terms to the left:
3(k+1)+11k-(2(4+5)+3)=0
We add all the numbers together, and all the variables
3(k+1)+11k-(29+3)=0
We add all the numbers together, and all the variables
11k+3(k+1)-32=0
We multiply parentheses
11k+3k+3-32=0
We add all the numbers together, and all the variables
14k-29=0
We move all terms containing k to the left, all other terms to the right
14k=29
k=29/14
k=2+1/14
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