3(k+1)+1k=2(4+5k)+3

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Solution for 3(k+1)+1k=2(4+5k)+3 equation: 



3(k+1)+1k=2(4+5k)+3

We move all terms to the left:

3(k+1)+1k-(2(4+5k)+3)=0

We add all the numbers together, and all the variables

3(k+1)+1k-(2(5k+4)+3)=0

We add all the numbers together, and all the variables

k+3(k+1)-(2(5k+4)+3)=0

We multiply parentheses

k+3k-(2(5k+4)+3)+3=0



We calculate terms in parentheses: -(2(5k+4)+3), so:

2(5k+4)+3

We multiply parentheses

10k+8+3

We add all the numbers together, and all the variables

10k+11

Back to the equation:

-(10k+11)



We add all the numbers together, and all the variables

4k-(10k+11)+3=0

We get rid of parentheses

4k-10k-11+3=0

We add all the numbers together, and all the variables

-6k-8=0

We move all terms containing k to the left, all other terms to the right

-6k=8

k=8/-6

k=-1+1/3

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