3(k+1)+7k=2(4+5k)-3

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Solution for 3(k+1)+7k=2(4+5k)-3 equation: 



3(k+1)+7k=2(4+5k)-3

We move all terms to the left:

3(k+1)+7k-(2(4+5k)-3)=0

We add all the numbers together, and all the variables

3(k+1)+7k-(2(5k+4)-3)=0

We add all the numbers together, and all the variables

7k+3(k+1)-(2(5k+4)-3)=0

We multiply parentheses

7k+3k-(2(5k+4)-3)+3=0



We calculate terms in parentheses: -(2(5k+4)-3), so:

2(5k+4)-3

We multiply parentheses

10k+8-3

We add all the numbers together, and all the variables

10k+5

Back to the equation:

-(10k+5)



We add all the numbers together, and all the variables

10k-(10k+5)+3=0

We get rid of parentheses

10k-10k-5+3=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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