3(k+1)=9k=

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Solution for 3(k+1)=9k= equation: 



3(k+1)=9k=

We move all terms to the left:

3(k+1)-(9k)=0

We add all the numbers together, and all the variables

-9k+3(k+1)=0

We multiply parentheses

-9k+3k+3=0

We add all the numbers together, and all the variables

-6k+3=0

We move all terms containing k to the left, all other terms to the right

-6k=-3

k=-3/-6

k=1/2

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