3(k+2)+10=20

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Solution for 3(k+2)+10=20 equation: 



3(k+2)+10=20

We move all terms to the left:

3(k+2)+10-(20)=0

We add all the numbers together, and all the variables

3(k+2)-10=0

We multiply parentheses

3k+6-10=0

We add all the numbers together, and all the variables

3k-4=0

We move all terms containing k to the left, all other terms to the right

3k=4

k=4/3

k=1+1/3

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