3(k+2)+2(k+3)=2k+3

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Solution for 3(k+2)+2(k+3)=2k+3 equation:


Simplifying
3(k + 2) + 2(k + 3) = 2k + 3

Reorder the terms:
3(2 + k) + 2(k + 3) = 2k + 3
(2 * 3 + k * 3) + 2(k + 3) = 2k + 3
(6 + 3k) + 2(k + 3) = 2k + 3

Reorder the terms:
6 + 3k + 2(3 + k) = 2k + 3
6 + 3k + (3 * 2 + k * 2) = 2k + 3
6 + 3k + (6 + 2k) = 2k + 3

Reorder the terms:
6 + 6 + 3k + 2k = 2k + 3

Combine like terms: 6 + 6 = 12
12 + 3k + 2k = 2k + 3

Combine like terms: 3k + 2k = 5k
12 + 5k = 2k + 3

Reorder the terms:
12 + 5k = 3 + 2k

Solving
12 + 5k = 3 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
12 + 5k + -2k = 3 + 2k + -2k

Combine like terms: 5k + -2k = 3k
12 + 3k = 3 + 2k + -2k

Combine like terms: 2k + -2k = 0
12 + 3k = 3 + 0
12 + 3k = 3

Add '-12' to each side of the equation.
12 + -12 + 3k = 3 + -12

Combine like terms: 12 + -12 = 0
0 + 3k = 3 + -12
3k = 3 + -12

Combine like terms: 3 + -12 = -9
3k = -9

Divide each side by '3'.
k = -3

Simplifying
k = -3

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