3(k+2)+2(k+4)=24

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Solution for 3(k+2)+2(k+4)=24 equation: 



3(k+2)+2(k+4)=24

We move all terms to the left:

3(k+2)+2(k+4)-(24)=0

We multiply parentheses

3k+2k+6+8-24=0

We add all the numbers together, and all the variables

5k-10=0

We move all terms containing k to the left, all other terms to the right

5k=10

k=10/5

k=2

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