3(k+2)+4(k-5)=0

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Solution for 3(k+2)+4(k-5)=0 equation: 



3(k+2)+4(k-5)=0

We multiply parentheses

3k+4k+6-20=0

We add all the numbers together, and all the variables

7k-14=0

We move all terms containing k to the left, all other terms to the right

7k=14

k=14/7

k=2

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