3(k+2)-5(k+2)=-2k-4

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Solution for 3(k+2)-5(k+2)=-2k-4 equation: 


Simplifying
3(k + 2) + -5(k + 2) = -2k + -4

Reorder the terms:
3(2 + k) + -5(k + 2) = -2k + -4
(2 * 3 + k * 3) + -5(k + 2) = -2k + -4
(6 + 3k) + -5(k + 2) = -2k + -4

Reorder the terms:
6 + 3k + -5(2 + k) = -2k + -4
6 + 3k + (2 * -5 + k * -5) = -2k + -4
6 + 3k + (-10 + -5k) = -2k + -4

Reorder the terms:
6 + -10 + 3k + -5k = -2k + -4

Combine like terms: 6 + -10 = -4
-4 + 3k + -5k = -2k + -4

Combine like terms: 3k + -5k = -2k
-4 + -2k = -2k + -4

Reorder the terms:
-4 + -2k = -4 + -2k

Add '4' to each side of the equation.
-4 + 4 + -2k = -4 + 4 + -2k

Combine like terms: -4 + 4 = 0
0 + -2k = -4 + 4 + -2k
-2k = -4 + 4 + -2k

Combine like terms: -4 + 4 = 0
-2k = 0 + -2k
-2k = -2k

Add '2k' to each side of the equation.
-2k + 2k = -2k + 2k

Combine like terms: -2k + 2k = 0
0 = -2k + 2k

Combine like terms: -2k + 2k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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