3(k+2)-5(k-2)=-2k-4

Solution for 3(k+2)-5(k-2)=-2k-4 equation:

Simplifying
3(k + 2) + -5(k + -2) = -2k + -4

Reorder the terms:
3(2 + k) + -5(k + -2) = -2k + -4
(2 * 3 + k * 3) + -5(k + -2) = -2k + -4
(6 + 3k) + -5(k + -2) = -2k + -4

Reorder the terms:
6 + 3k + -5(-2 + k) = -2k + -4
6 + 3k + (-2 * -5 + k * -5) = -2k + -4
6 + 3k + (10 + -5k) = -2k + -4

Reorder the terms:
6 + 10 + 3k + -5k = -2k + -4

Combine like terms: 6 + 10 = 16
16 + 3k + -5k = -2k + -4

Combine like terms: 3k + -5k = -2k
16 + -2k = -2k + -4

Reorder the terms:
16 + -2k = -4 + -2k

Add '2k' to each side of the equation.
16 + -2k + 2k = -4 + -2k + 2k

Combine like terms: -2k + 2k = 0
16 + 0 = -4 + -2k + 2k
16 = -4 + -2k + 2k

Combine like terms: -2k + 2k = 0
16 = -4 + 0
16 = -4

Solving
16 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.