3(k+2)=-3(k-2)

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Solution for 3(k+2)=-3(k-2) equation: 



3(k+2)=-3(k-2)

We move all terms to the left:

3(k+2)-(-3(k-2))=0

We multiply parentheses

3k-(-3(k-2))+6=0



We calculate terms in parentheses: -(-3(k-2)), so:

-3(k-2)

We multiply parentheses

-3k+6

Back to the equation:

-(-3k+6)



We get rid of parentheses

3k+3k-6+6=0

We add all the numbers together, and all the variables

6k=0

k=0/6

k=0

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