3(k+2)=12k

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Solution for 3(k+2)=12k equation: 



3(k+2)=12k

We move all terms to the left:

3(k+2)-(12k)=0

We add all the numbers together, and all the variables

-12k+3(k+2)=0

We multiply parentheses

-12k+3k+6=0

We add all the numbers together, and all the variables

-9k+6=0

We move all terms containing k to the left, all other terms to the right

-9k=-6

k=-6/-9

k=2/3

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