3(k+2)=6(k-7)

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Solution for 3(k+2)=6(k-7) equation:



3(k+2)=6(k-7)
We move all terms to the left:
3(k+2)-(6(k-7))=0
We multiply parentheses
3k-(6(k-7))+6=0
We calculate terms in parentheses: -(6(k-7)), so:
6(k-7)
We multiply parentheses
6k-42
Back to the equation:
-(6k-42)
We get rid of parentheses
3k-6k+42+6=0
We add all the numbers together, and all the variables
-3k+48=0
We move all terms containing k to the left, all other terms to the right
-3k=-48
k=-48/-3
k=+16

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