3(k+2)=6k-(k-4)

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Solution for 3(k+2)=6k-(k-4) equation:



3(k+2)=6k-(k-4)
We move all terms to the left:
3(k+2)-(6k-(k-4))=0
We multiply parentheses
3k-(6k-(k-4))+6=0
We calculate terms in parentheses: -(6k-(k-4)), so:
6k-(k-4)
We get rid of parentheses
6k-k+4
We add all the numbers together, and all the variables
5k+4
Back to the equation:
-(5k+4)
We get rid of parentheses
3k-5k-4+6=0
We add all the numbers together, and all the variables
-2k+2=0
We move all terms containing k to the left, all other terms to the right
-2k=-2
k=-2/-2
k=1

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