3(k+3)-12=-3(1-k)

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Solution for 3(k+3)-12=-3(1-k) equation: 



3(k+3)-12=-3(1-k)

We move all terms to the left:

3(k+3)-12-(-3(1-k))=0

We add all the numbers together, and all the variables

3(k+3)-(-3(-1k+1))-12=0

We multiply parentheses

3k-(-3(-1k+1))+9-12=0



We calculate terms in parentheses: -(-3(-1k+1)), so:

-3(-1k+1)

We multiply parentheses

3k-3

Back to the equation:

-(3k-3)



We add all the numbers together, and all the variables

3k-(3k-3)-3=0

We get rid of parentheses

3k-3k+3-3=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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