3(k+3)=-26-4k

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Solution for 3(k+3)=-26-4k equation: 



3(k+3)=-26-4k

We move all terms to the left:

3(k+3)-(-26-4k)=0

We add all the numbers together, and all the variables

3(k+3)-(-4k-26)=0

We multiply parentheses

3k-(-4k-26)+9=0

We get rid of parentheses

3k+4k+26+9=0

We add all the numbers together, and all the variables

7k+35=0

We move all terms containing k to the left, all other terms to the right

7k=-35

k=-35/7

k=-5

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