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3(k+4)-2(k+1)-13=20
We move all terms to the left:
3(k+4)-2(k+1)-13-(20)=0
We add all the numbers together, and all the variables
3(k+4)-2(k+1)-33=0
We multiply parentheses
3k-2k+12-2-33=0
We add all the numbers together, and all the variables
k-23=0
We move all terms containing k to the left, all other terms to the right
k=23
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