3(k+4)/7=1

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Solution for 3(k+4)/7=1 equation: 



3(k+4)/7=1

We move all terms to the left:

3(k+4)/7-(1)=0

We multiply all the terms by the denominator


3(k+4)-1*7=0

We add all the numbers together, and all the variables

3(k+4)-7=0

We multiply parentheses

3k+12-7=0

We add all the numbers together, and all the variables

3k+5=0

We move all terms containing k to the left, all other terms to the right

3k=-5

k=-5/3

k=-1+2/3

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