3(k+4)=2(k-9)

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Solution for 3(k+4)=2(k-9) equation: 



3(k+4)=2(k-9)

We move all terms to the left:

3(k+4)-(2(k-9))=0

We multiply parentheses

3k-(2(k-9))+12=0



We calculate terms in parentheses: -(2(k-9)), so:

2(k-9)

We multiply parentheses

2k-18

Back to the equation:

-(2k-18)



We get rid of parentheses

3k-2k+18+12=0

We add all the numbers together, and all the variables

k+30=0

We move all terms containing k to the left, all other terms to the right

k=-30

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