3(k+4)=3k+12

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Solution for 3(k+4)=3k+12 equation: 


Simplifying
3(k + 4) = 3k + 12

Reorder the terms:
3(4 + k) = 3k + 12
(4 * 3 + k * 3) = 3k + 12
(12 + 3k) = 3k + 12

Reorder the terms:
12 + 3k = 12 + 3k

Add '-12' to each side of the equation.
12 + -12 + 3k = 12 + -12 + 3k

Combine like terms: 12 + -12 = 0
0 + 3k = 12 + -12 + 3k
3k = 12 + -12 + 3k

Combine like terms: 12 + -12 = 0
3k = 0 + 3k
3k = 3k

Add '-3k' to each side of the equation.
3k + -3k = 3k + -3k

Combine like terms: 3k + -3k = 0
0 = 3k + -3k

Combine like terms: 3k + -3k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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