3(k+4)=4(k+2)

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Solution for 3(k+4)=4(k+2) equation: 



3(k+4)=4(k+2)

We move all terms to the left:

3(k+4)-(4(k+2))=0

We multiply parentheses

3k-(4(k+2))+12=0



We calculate terms in parentheses: -(4(k+2)), so:

4(k+2)

We multiply parentheses

4k+8

Back to the equation:

-(4k+8)



We get rid of parentheses

3k-4k-8+12=0

We add all the numbers together, and all the variables

-1k+4=0

We move all terms containing k to the left, all other terms to the right

-k=-4

k=-4/-1

k=+4

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