3(k+4)=4(k+2)

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Solution for 3(k+4)=4(k+2) equation:



3(k+4)=4(k+2)
We move all terms to the left:
3(k+4)-(4(k+2))=0
We multiply parentheses
3k-(4(k+2))+12=0
We calculate terms in parentheses: -(4(k+2)), so:
4(k+2)
We multiply parentheses
4k+8
Back to the equation:
-(4k+8)
We get rid of parentheses
3k-4k-8+12=0
We add all the numbers together, and all the variables
-1k+4=0
We move all terms containing k to the left, all other terms to the right
-k=-4
k=-4/-1
k=+4

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