3(k+5)+2=4(k+3)

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Solution for 3(k+5)+2=4(k+3) equation: 



3(k+5)+2=4(k+3)

We move all terms to the left:

3(k+5)+2-(4(k+3))=0

We multiply parentheses

3k-(4(k+3))+15+2=0



We calculate terms in parentheses: -(4(k+3)), so:

4(k+3)

We multiply parentheses

4k+12

Back to the equation:

-(4k+12)



We add all the numbers together, and all the variables

3k-(4k+12)+17=0

We get rid of parentheses

3k-4k-12+17=0

We add all the numbers together, and all the variables

-1k+5=0

We move all terms containing k to the left, all other terms to the right

-k=-5

k=-5/-1

k=+5

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