3(k+5)=-29(3k-6)

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Solution for 3(k+5)=-29(3k-6) equation: 



3(k+5)=-29(3k-6)

We move all terms to the left:

3(k+5)-(-29(3k-6))=0

We multiply parentheses

3k-(-29(3k-6))+15=0



We calculate terms in parentheses: -(-29(3k-6)), so:

-29(3k-6)

We multiply parentheses

-87k+174

Back to the equation:

-(-87k+174)



We get rid of parentheses

3k+87k-174+15=0

We add all the numbers together, and all the variables

90k-159=0

We move all terms containing k to the left, all other terms to the right

90k=159

k=159/90

k=1+23/30

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