3(k+5)=2(3k+6)

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Solution for 3(k+5)=2(3k+6) equation: 



3(k+5)=2(3k+6)

We move all terms to the left:

3(k+5)-(2(3k+6))=0

We multiply parentheses

3k-(2(3k+6))+15=0



We calculate terms in parentheses: -(2(3k+6)), so:

2(3k+6)

We multiply parentheses

6k+12

Back to the equation:

-(6k+12)



We get rid of parentheses

3k-6k-12+15=0

We add all the numbers together, and all the variables

-3k+3=0

We move all terms containing k to the left, all other terms to the right

-3k=-3

k=-3/-3

k=1

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