3(k+5)=2(6-k)

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Solution for 3(k+5)=2(6-k) equation: 



3(k+5)=2(6-k)

We move all terms to the left:

3(k+5)-(2(6-k))=0

We add all the numbers together, and all the variables

3(k+5)-(2(-1k+6))=0

We multiply parentheses

3k-(2(-1k+6))+15=0



We calculate terms in parentheses: -(2(-1k+6)), so:

2(-1k+6)

We multiply parentheses

-2k+12

Back to the equation:

-(-2k+12)



We get rid of parentheses

3k+2k-12+15=0

We add all the numbers together, and all the variables

5k+3=0

We move all terms containing k to the left, all other terms to the right

5k=-3

k=-3/5

k=-3/5

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