3(k+5)=4(k-1)

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Solution for 3(k+5)=4(k-1) equation: 



3(k+5)=4(k-1)

We move all terms to the left:

3(k+5)-(4(k-1))=0

We multiply parentheses

3k-(4(k-1))+15=0



We calculate terms in parentheses: -(4(k-1)), so:

4(k-1)

We multiply parentheses

4k-4

Back to the equation:

-(4k-4)



We get rid of parentheses

3k-4k+4+15=0

We add all the numbers together, and all the variables

-1k+19=0

We move all terms containing k to the left, all other terms to the right

-k=-19

k=-19/-1

k=+19

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