3(k-1)+11k=2(4+5k)+3

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Solution for 3(k-1)+11k=2(4+5k)+3 equation: 



3(k-1)+11k=2(4+5k)+3

We move all terms to the left:

3(k-1)+11k-(2(4+5k)+3)=0

We add all the numbers together, and all the variables

3(k-1)+11k-(2(5k+4)+3)=0

We add all the numbers together, and all the variables

11k+3(k-1)-(2(5k+4)+3)=0

We multiply parentheses

11k+3k-(2(5k+4)+3)-3=0



We calculate terms in parentheses: -(2(5k+4)+3), so:

2(5k+4)+3

We multiply parentheses

10k+8+3

We add all the numbers together, and all the variables

10k+11

Back to the equation:

-(10k+11)



We add all the numbers together, and all the variables

14k-(10k+11)-3=0

We get rid of parentheses

14k-10k-11-3=0

We add all the numbers together, and all the variables

4k-14=0

We move all terms containing k to the left, all other terms to the right

4k=14

k=14/4

k=3+1/2

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