3(k-1)+2=k+4

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Solution for 3(k-1)+2=k+4 equation: 



3(k-1)+2=k+4

We move all terms to the left:

3(k-1)+2-(k+4)=0

We multiply parentheses

3k-(k+4)-3+2=0

We get rid of parentheses

3k-k-4-3+2=0

We add all the numbers together, and all the variables

2k-5=0

We move all terms containing k to the left, all other terms to the right

2k=5

k=5/2

k=2+1/2

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