3(k-1)+2=k+4k

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Solution for 3(k-1)+2=k+4k equation: 



3(k-1)+2=k+4k

We move all terms to the left:

3(k-1)+2-(k+4k)=0

We add all the numbers together, and all the variables

3(k-1)-(+5k)+2=0

We multiply parentheses

3k-(+5k)-3+2=0

We get rid of parentheses

3k-5k-3+2=0

We add all the numbers together, and all the variables

-2k-1=0

We move all terms containing k to the left, all other terms to the right

-2k=1

k=1/-2

k=-1/2

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