3(k-1)-3(2k+2)=2

Solution for 3(k-1)-3(2k+2)=2 equation:

Simplifying
3(k + -1) + -3(2k + 2) = 2

Reorder the terms:
3(-1 + k) + -3(2k + 2) = 2
(-1 * 3 + k * 3) + -3(2k + 2) = 2
(-3 + 3k) + -3(2k + 2) = 2

Reorder the terms:
-3 + 3k + -3(2 + 2k) = 2
-3 + 3k + (2 * -3 + 2k * -3) = 2
-3 + 3k + (-6 + -6k) = 2

Reorder the terms:
-3 + -6 + 3k + -6k = 2

Combine like terms: -3 + -6 = -9
-9 + 3k + -6k = 2

Combine like terms: 3k + -6k = -3k
-9 + -3k = 2

Solving
-9 + -3k = 2

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + -3k = 2 + 9

Combine like terms: -9 + 9 = 0
0 + -3k = 2 + 9
-3k = 2 + 9

Combine like terms: 2 + 9 = 11
-3k = 11

Divide each side by '-3'.
k = -3.666666667

Simplifying
k = -3.666666667