3(k-1)=2(k+3)

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Solution for 3(k-1)=2(k+3) equation: 



3(k-1)=2(k+3)

We move all terms to the left:

3(k-1)-(2(k+3))=0

We multiply parentheses

3k-(2(k+3))-3=0



We calculate terms in parentheses: -(2(k+3)), so:

2(k+3)

We multiply parentheses

2k+6

Back to the equation:

-(2k+6)



We get rid of parentheses

3k-2k-6-3=0

We add all the numbers together, and all the variables

k-9=0

We move all terms containing k to the left, all other terms to the right

k=9

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