3(k-1)=2k-2

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Solution for 3(k-1)=2k-2 equation: 



3(k-1)=2k-2

We move all terms to the left:

3(k-1)-(2k-2)=0

We multiply parentheses

3k-(2k-2)-3=0

We get rid of parentheses

3k-2k+2-3=0

We add all the numbers together, and all the variables

k-1=0

We move all terms containing k to the left, all other terms to the right

k=1

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