3(k-12)=48

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Solution for 3(k-12)=48 equation: 



3(k-12)=48

We move all terms to the left:

3(k-12)-(48)=0

We multiply parentheses

3k-36-48=0

We add all the numbers together, and all the variables

3k-84=0

We move all terms containing k to the left, all other terms to the right

3k=84

k=84/3

k=28

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