3(k-15)=6

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Solution for 3(k-15)=6 equation: 



3(k-15)=6

We move all terms to the left:

3(k-15)-(6)=0

We multiply parentheses

3k-45-6=0

We add all the numbers together, and all the variables

3k-51=0

We move all terms containing k to the left, all other terms to the right

3k=51

k=51/3

k=17

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