3(k-19)=-6

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Solution for 3(k-19)=-6 equation:



3(k-19)=-6
We move all terms to the left:
3(k-19)-(-6)=0
We add all the numbers together, and all the variables
3(k-19)+6=0
We multiply parentheses
3k-57+6=0
We add all the numbers together, and all the variables
3k-51=0
We move all terms containing k to the left, all other terms to the right
3k=51
k=51/3
k=17

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