3(k-2)+2(-2k-5)=-17

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Solution for 3(k-2)+2(-2k-5)=-17 equation:


Simplifying
3(k + -2) + 2(-2k + -5) = -17

Reorder the terms:
3(-2 + k) + 2(-2k + -5) = -17
(-2 * 3 + k * 3) + 2(-2k + -5) = -17
(-6 + 3k) + 2(-2k + -5) = -17

Reorder the terms:
-6 + 3k + 2(-5 + -2k) = -17
-6 + 3k + (-5 * 2 + -2k * 2) = -17
-6 + 3k + (-10 + -4k) = -17

Reorder the terms:
-6 + -10 + 3k + -4k = -17

Combine like terms: -6 + -10 = -16
-16 + 3k + -4k = -17

Combine like terms: 3k + -4k = -1k
-16 + -1k = -17

Solving
-16 + -1k = -17

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -1k = -17 + 16

Combine like terms: -16 + 16 = 0
0 + -1k = -17 + 16
-1k = -17 + 16

Combine like terms: -17 + 16 = -1
-1k = -1

Divide each side by '-1'.
k = 1

Simplifying
k = 1

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