3(k-2)-1=2-5(k+5)

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Solution for 3(k-2)-1=2-5(k+5) equation: 



3(k-2)-1=2-5(k+5)

We move all terms to the left:

3(k-2)-1-(2-5(k+5))=0

We multiply parentheses

3k-(2-5(k+5))-6-1=0



We calculate terms in parentheses: -(2-5(k+5)), so:

2-5(k+5)

determiningTheFunctionDomain
-5(k+5)+2

We multiply parentheses

-5k-25+2

We add all the numbers together, and all the variables

-5k-23

Back to the equation:

-(-5k-23)



We add all the numbers together, and all the variables

3k-(-5k-23)-7=0

We get rid of parentheses

3k+5k+23-7=0

We add all the numbers together, and all the variables

8k+16=0

We move all terms containing k to the left, all other terms to the right

8k=-16

k=-16/8

k=-2

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